continue 继续执行循环,break跳出循环。

[root@hunt1574 ~]# cat test2.sh

#!/bin/bash for index in 1 2 3 4 5 6 7         do                 if [ $index -le 3 ];then                         echo "continue"                         continue                 fi              echo $index                 if [ $index -ge 6 ];then                         echo "break"                         break                 fi         done

[root@hunt1574 ~]# sh test2.sh

continue continue continue 4 5 6 break